On Mon, Jul 19, 2004 at 06:33:49PM +0100, Tom Knight wrote:
> 
> The solution is to do it like this:
> 
> [ `use foo` ] && bar
> 
> Which returns true if foo is in USE, but doesn't output the USE flag. 

OK, have had a word with a few people on #g-dev, the way that the use
function works is going to change so that it doesn't output the use flag, so
ignore what I said in the last message.

tom


-- 
Tom Knight
tomk@gentoo.org
GPG Public Key: http://dev.gentoo.org/~tomk/tomk.asc