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From: Aron Griffis <agriffis@gentoo.org>
To: gentoo-dev@cvs.gentoo.org
Subject: Re: [gentoo-dev] Short Question about sed
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Date: Tue Oct  9 11:39:02 2001
X-Original-Date: Tue, 9 Oct 2001 12:39:04 -0500
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Sebastian Werner wrote:	[Tue Oct 09 2001, 01:27:53AM EST]
> i need a solution in a script to replace all backslashes (\). I know that i
> how i replace slashes (/) (sed s/"\/"/"someelse"/g) but how i replace
> backslashes.

sed 's/\\/replacement/'

Note that if you're replacing in a shell variable, you might consider
using the bash replacement syntax instead of calling out to sed.

Usage:

    VAR="${VAR#patt}"         # snip shortest match from front

    VAR="${VAR##path}"        # snip longest match from front

    VAR="${VAR%patt}"         # snip shortest match from end

    VAR="${VAR%%path}"        # snip longest match from end

    VAR="${VAR/patt/repl}"    # replace first occurance

    VAR="${VAR//patt/repl}"   # replace all occurances

    VAR="${VAR/#patt/repl}"   # replace, rooted to beginning (^ in regex)

    VAR="${VAR/%patt/repl}"   # replace, rooted to end ($ in regex)

Examples (not necessarily practical):

    progname="${0##*/}"       # snip entire path from program name

    newvar="${oldvar//\\\\/backslash}"  # note that \\\\ matches one backslash!

    set -- "${@/#/$D/}"       # prepend $D/ to all args

    newarray=("${@/#/$D}")    # same as last example, but put in newarray

Aron